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Style fix - libzahl - big integer library
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---
commit 4d2e79e7eec793a557c26d1253bcfc13f6b555d6
parent 243a542dce0f8da6fc3ac43d5e5fcb144559b507
Author: Mattias Andrée <[email protected]>
Date: Mon, 25 Jul 2016 15:58:29 +0200
Style fix
Signed-off-by: Mattias Andrée <[email protected]>
Diffstat:
M doc/exercises.tex | 8 ++++----
1 file changed, 4 insertions(+), 4 deletions(-)
---
diff --git a/doc/exercises.tex b/doc/exercises.tex
@@ -168,13 +168,13 @@ For improved performance, instead of using \texttt{zmod},
you can use the recursive function
%
\( \displaystyle{
- k ~\mbox{Mod}~ 2^n - 1 =
+ k \mod (2^n - 1) =
\left (
- (k ~\mbox{Mod}~ 2^n) + \lfloor k \div 2^n \rfloor
- \right ) ~\mbox{Mod}~ 2^n - 1,
+ (k \mod 2^n) + \lfloor k \div 2^n \rfloor
+ \right ) \mod (2^n - 1),
}\)
%
-where $k ~\mbox{Mod}~ 2^n$ is efficiently calculated
+where $k \mod 2^n$ is efficiently calculated
using \texttt{zand($k$, $2^n - 1$)}. (This optimisation
is not part of the difficulty rating of this problem.)
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