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Post As73H5gFwuVVbzcorY by [email protected] |
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Post #As73H5gFwuVVbzcorY by [email protected] |
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x= \frac{-b' \pm \sqrt{(b')^2-ac}}{a} |
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Post #As73H5oPSb1s1HRKZU by [email protected] |
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@fauli1221 Greetings from non-Latex rendering Ponyverse. But I still know it&#… |
