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Post AmfBe6GNQrEvAeuvI0 by [email protected] |
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Post #AmeTs1XrNHLubpvKtM by [email protected] |
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Let \(\pi: SO(n+1)\rightarrow S^n\) be the map given by\[\pi(P)=Px\]where \(x\i… |
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Post #AmeTs1hQnh0b5WOyoK by [email protected] |
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@Diffgeometer1 - interesting puzzle! To me the obvious approach is to start w… |
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Post #AmeX6ihK1xKmMT35f6 by [email protected] |
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@Diffgeometer1 - to compute the de Rham cohomology of SO(n) we should probably … |
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Post #Amea1ex8pHWlA4j7lg by [email protected] |
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@Diffgeometer1 - let's see if I can prove SO(5) ≇ S⁴ × SO(4) using the… |
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Post #AmeeBpZWbCiQoBmmmm by [email protected] |
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@johncarlosbaez @Diffgeometer1 de Rham cohomology works half the time for this … |
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Post #AmeidHWrAC1v9PsneC by [email protected] |
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@Diffgeometer1 It's trivial(isable) for n=1, and I'm pretty sure for 3,… |
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Post #AmeidHiCU16VibBrKS by [email protected] |
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@highergeometer @Diffgeometer1 Oh, you're right: this is exactly equivalent… |
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Post #AmeiuR3D0yWbbaC99k by [email protected] |
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@oantolin - and don't forget S⁰! 😉 Let me summarize for @Diffgeomete… |
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Post #Amf3Io436Il10uUDMe by [email protected] |
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@oantolin @highergeometer @Diffgeometer1 - and don't forget S⁰! 😉 Th… |
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Post #AmfBe6GNQrEvAeuvI0 by [email protected] |
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@johncarlosbaez @oantolin @highergeometer That's a big help! Thank you ver… |
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Post #AmfOKs5LDidP6IutRw by [email protected] |
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@oantolin - that's really cool! It's neat how the additional generato… |
