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tset F and G in boundary cells - ns2dfd - 2D finite difference Navier Stokes so… |
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git clone git://src.adamsgaard.dk/ns2dfd |
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--- |
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commit 58f406613c0c30ec7f453095e1d9399539341ad5 |
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parent e3c43ff247f84337b66a8782d923b7e293ae03d5 |
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Author: Anders Damsgaard <[email protected]> |
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Date: Tue, 4 Mar 2014 11:27:50 +0100 |
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set F and G in boundary cells |
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Diffstat: |
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M src/main.c | 2 ++ |
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M src/solution.c | 10 ++++++++++ |
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2 files changed, 12 insertions(+), 0 deletions(-) |
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--- |
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diff --git a/src/main.c b/src/main.c |
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t@@ -82,6 +82,8 @@ int main(int argc, char** argv) |
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allocate_matrix(&RES, nx+2, ny+2); |
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print_matrix("P", P, nx+2, ny+2); |
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+ print_matrix("U", U, nx+2, ny+2); |
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+ print_matrix("V", V, nx+2, ny+2); |
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while (t <= t_end+dt) { |
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dt = select_time_step(tau, re, dx, dy, nx, ny, U, V); |
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diff --git a/src/solution.c b/src/solution.c |
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t@@ -88,6 +88,16 @@ void compute_f_g(double **F, double **G, |
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- duv_dx(U, V, i, j, dx, gamma) |
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- dvv_dy(V, i, j, dy, gamma) |
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+ gy); |
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+ |
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+ for (j=1; j<=ny; j++) { |
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+ F[0][j] = U[0][j]; |
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+ F[nx][j] = U[nx][j]; |
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+ } |
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+ |
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+ for (i=1; i<=nx; i++) { |
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+ G[i][0] = V[i][0]; |
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+ G[i][ny] = V[i][ny]; |
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+ } |
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} |
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/* Find the right hand side value of the Poisson equation */ |
