Aihuxv.110
net.math
utzoo!decvax!harpo!ihnss!ihuxv!lambert
Wed May  5 14:12:57 1982
Re: 2=1 by Decot
The right hand side of your second equation is not a continuous
function, and bad things happen when
you differentiate a discontinuous function --  in this case, one
which is only defined for integral values of x.

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