/* This script converts "space-dot" fonts to binary "glyph rows". One byte for
* each row. In a 5x7 font, each glyph thus use 7 bytes.
* Resulting bytes are aligned to the **left** of the byte. Therefore, for
* a 5-bit wide char, ". . ." translates to 0b10101000
* Left-aligned bytes are easier to work with when compositing glyphs.
*/
int main(int argc, char **argv)
{
if (argc != 2) {
fprintf(stderr, "Usage: ./fontcompile fpath\n");
return 1;
}
char *fn = basename(argv[1]);
if (!fn) {
return 1;
}
int w = 0;
if ((fn[0] >= '3') && (fn[0] <= '8')) {
w = fn[0] - '0';
}
int h = 0;
if ((fn[2] >= '3') && (fn[2] <= '8')) {
h = fn[2] - '0';
}
if (!w || !h || fn[1] != 'x') {
fprintf(stderr, "Not a font filename: (3-8)x(3-8).txt.\n");
return 1;
}
fprintf(stderr, "Reading a %d x %d font\n", w, h);
FILE *fp = fopen(argv[1], "r");
if (!fp) {
fprintf(stderr, "Can't open %s.\n", argv[1]);
return 1;
}
// We start the binary data with our first char, space, which is not in our
// input but needs to be in our output.
for (int i=0; i<h; i++) {
putchar(0);
}
int lineno = 1;
char buf[0x10];
while (fgets(buf, 0x10, fp)) {
size_t l = strlen(buf);
if (l > w+1) { // +1 because of the newline char.
fprintf(stderr, "Line %d too long.\n", lineno);
fclose(fp);
return 1;
}
// line can be narrower than width. It's padded with spaces.
while (l < w+1) {
buf[l] = ' ';
l++;
}
unsigned char c = 0;
for (int i=0; i<w; i++) {
if (buf[i] == '.') {
c |= (1 << (7-i));
}
}
putchar(c);
lineno++;
}
fclose(fp);
return 0;
}
