Subj : help!
To : All
From : Chris Hoppman
Date : Mon Feb 23 2004 04:31 am
Was wondering what this is about.
b:boolean;
by:byte;
---
b := (by and 6 = 6);
---
I have it in two places in my com routines that I am tring to convert to asm
and don't really know how it goes about evaluating this experssion. So, don't
know if I can convert it.
I saw in the help file. If by = 6 then it's true/ if by <> 6 then it is false
and via versa, but what does = 6 at the end of it play.
I understand this. b := (by and 6), but don't understand b:=(by and 6 = 6);
I havn't had time to do some test to figure it out and hoped for a quick
answer in this group.
